Letter Substitutions
Hints:
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A + B = 16, which means there’s a carry into the tens place.
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D + D results in a number with E in the ones place and a carry—written as 1E.
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Also, you’re told that D is one more than E.
Put all that together to figure out the digits. Try out possible values that satisfy all three conditions.
Solutions:
Puzzle 1: A + BB = C6
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We’re told A + B = 16, and that triggers a carry into the tens place, so:
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The tens digit (C) must be one greater than B → C = B + 1
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What two digits add up to 16 and differ by 2?
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A = 9, B = 7 → A + B = 16, and C = 8 (since 7 + 1 = 8)
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Let’s check:
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9 + 77 = 86 → Matches the form: C6 = 86
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Answer: 9 + 77 = 86
Puzzle 2: D + ED = DE
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Here, D + D gives a two-digit number ending in E, so:
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D + D = 1E
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D is one more than E
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Try possible values for D + D = 1E:
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5 + 5 = 10 → E = 0 ❌
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6 + 6 = 12 → E = 2 ❌
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7 + 7 = 14 → E = 4 ❌
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8 + 8 = 16 → E = 6 ❌
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9 + 9 = 18 → E = 8 ✔
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Now check:
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D = 9, E = 8
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9 + 89 = 98 → Works perfectly
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Answer: 9 + 89 = 98
